主页 / coding / 问题 / 78303477
Accepted
feffe
Asked: 2024-04-10 17:37:22 +0800 CST

动态访问 AzureDevOps YAML 管道参数

  • 772

我有一个模板，它获取一个对象参数和一个用于寻址对象中的值的字符串参数。这里我有不同的方法来打印值：

- name: valueName # the name of the attribute
  type: string

- name: secrets # array with secret info data (name, value)
  type: object
  default: []

jobs:
- ${{each secret in parameters.secrets}}:
    - job:
      steps:
      - script: |
          echo "${{ secret['Development'] }}"
      - script: |
          echo "secret['${{ parameters.valueName}}']"
      - script: |
          echo "${{ secret['${{ parameters.valueName}}'] }}"

我想要实现的是根据 valueName 参数的值来访问密钥的值。所以该对象可能看起来像这样：

- name: secrets    
  type: object
  default: 
  - name: 'dbpassword'
    Development: 'demokey1'
    Staging: 'demokey2'
    Production: 'demokey3'

然而，这就是 3 个作业步骤的输出：

echo "demokey1"
echo "secret['Development']"
echo ""

有没有办法通过提供名称作为另一个参数来解析参数值？

azure-devops

2 个回答

  1. 如果我理解正确，您将尝试获取作为参数传递的环境的秘密valueName：

    • Production
    • Staging
    • Development

    您可以使用常规变量而不是复杂的参数来简化管道的设计。

    第一步是创建一个变量模板：

    # /pipelines/variables/secret-variables.yaml

parameters:
  - name: environment
    displayName: 'Environment name (e.g. Production, Staging, Development)'
    type: string

variables:
  # Note: for sensitive data, it is recommended to use variables groups!!!

  - ${{ if eq(parameters.environment, 'Development') }}:
    - name: secret
      value: demokey1
  
  - ${{ if eq(parameters.environment, 'Staging') }}:
    - name: secret
      value: demokey2
  
  - ${{ if eq(parameters.environment, 'Production') }}:
    - name: secret
      value: demokey3

    然后您只需要引用设置参数的变量模板environment- 示例管道：

    name: test-pipeline-4

parameters:
  - name: environment
    displayName: 'Environment name'
    type: string
    default: Development
    values:
      - Development
      - Staging
      - Production

trigger: none

pool: 
  vmImage: 'ubuntu-latest'

jobs:
  - job: test
    variables:
      - template: /pipelines/variables/secret-variables.yaml
        parameters:
          environment: ${{ parameters.environment }}
    steps:
      - script: |
          echo "Secret: $(secret)"
        displayName: 'Print secret'
    • 1
  2. Best Answer

    在 Azure Pipelines 中，不支持在另一个变量/参数的名称中使用变量/参数。

    对于您的情况，您确实喜欢如下示例所示：

    parameters:
- name: valueName
  type: string
  default: 'Development'

- name: secrets
  type: object
  default:
  - name: 'sec01'
    Development: 'dev01'
    Staging: 'stage01'
    Production: 'prod01'
  - name: 'sec02'
    Development: 'dev02'
    Staging: 'stage02'
    Production: 'prod02'

stages:
- stage: A
  jobs:
  - ${{ each secret in parameters.secrets }}:
    - job: A_${{ secret.name }}
      steps:
      . . .

      - ${{ each item in secret }}:
        - ${{ if eq(item.Key, parameters.valueName) }}:
          - task: Bash@3
            displayName: 'Show Infor'
            inputs:
              targetType: inline
              script: |
                echo "item.Key = ${{ item.Key }}"
                echo "item.Value = ${{ item.Value }}"
                echo "parameters.valueName = ${{ parameters.valueName }}"

    在此输入图像描述

    • 1

相关问题