Início / dba / Perguntas / 196905
Accepted
Agnel Amodia
Asked: 2018-02-03 06:09:17 +0800 CST

Como exibir todas as datas no intervalo de datas agrupadas por datas?

  • 772

Suponha que eu tenha uma tabela chamada “produtos”:

Productive product-name   product-quantity  created-date
111            ABC          10               1/10/2018
222            XYZ          20               1/10/2018
333            PQR          30               1/11/2018
444            MNC          40               1/15/2018
555            DEF          50               1/11/2018

Se eu executar esta consulta:

Select convert(date,createddate,101), count(product-quantity) from products
Where created-date > 1/9/2018 and created-date < 1/16/1018
group by convert(date,createddate,101)

O que me dará saídas como

created-date.  product-quantity
1/10/2018            30
1/11/2018            80
1/15/2018            40

Eu quero alcançar:

created-date.  product-quantity
1/10/2018            30
1/11/2018            80
1/12/2018            00
1/13/2018            00
1/14/2018            00
1/15/2018            40

Como eu posso fazer isso?

sql-server group-by

1 respostas

  1. Best Answer

    Uma implementação básica de uma tabela de calendário.

    CREATE TABLE Calendar(cDate datetime, cDay int, cDayOfWeek int, cDayName varchar(20));

DECLARE @date date = '20180101';
WHILE @date <= '20180131'
BEGIN
    INSERT INTO Calendar VALUES (@date, DAY(@date), DATEPART(weekday, @date), DATENAME(weekday, @date));
    SET @date = DATEADD(day, 1, @date);
END
GO

    31 linhas afetadas

    CREATE TABLE products(Productive int, Name char(3), Qty int, Created date);
INSERT INTO products VALUES
(111, 'ABC', 10, '1/10/2018'),
(222, 'XYZ', 20, '1/10/2018'),
(333, 'PQR', 30, '1/11/2018'),
(444, 'MNC', 40, '1/15/2018'),
(555, 'DEF', 50, '1/11/2018');
GO

    5 linhas afetadas

    Observe que usei um LEFT JOIN para obter todos os registros da tabela de calendário e apenas os registros que correspondem à tabela de produtos.

    SELECT     c.cDate AS Created, COALESCE(Qty, 0) AS Qty
FROM       Calendar c
LEFT JOIN  (SELECT   CONVERT(date, Created, 101) AS [Created],
                     COUNT(Qty) AS [Qty]
            FROM     products
            GROUP BY CONVERT(date, Created, 101)) p
ON         p.Created = c.cDate
WHERE      c.cDate >= (SELECT MIN(Created) FROM products)
AND        c.cDate <= (SELECT MAX(Created) FROM products);
GO

    Criado | Quantidade
:------------------ | --:
01/10/2018 00:00:00 | 2
01/11/2018 00:00:00 | 2
01/12/2018 00:00:00 | 0
13/01/2018 00:00:00 | 0
14/01/2018 00:00:00 | 0
15/01/2018 00:00:00 | 1

    dbfiddle aqui

    • 0

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